If in doubt, write down the acceleration equation relating the motion of points A and G. This will give you the answer to your question. As Garrett points out, since the bar is at rest when the force ...

The solution for this problem is a straight-forward application of our two rigid body kinematics equations relating the motion of point A back to point O: v A = v O + ω x r A/O a A = a O + α x r A/O – ...